solve the differential equation y^2e^xy^2 +4x^3 dx+ 2xye^xy^2 −3y^2 dy = 0.

asked by guest
on Mar 23, 2025 at 11:50 am



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Investigate the equation: y2exy2+4x3dx+2xyexy2−3y2dy=0{y}^{2} {e}^{x} {y}^{2} + 4 {x}^{3} d x + 2 x y {e}^{x} {y}^{2} - 3 {y}^{2} d y = 0.

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