Math Problem Solver

\[ \frac{1}{3} + \frac{1}{9} + \frac{1}{18} = \frac{1}{2} = 0.5 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{3}\), \(\frac{1}{9}\), and \(\frac{1}{18}\) is \(18\). \[ \begin{aligned} \frac{1}{3} + \frac{1}{9} + \frac{1}{18} &= \frac{1 \cdot 6}{3 \cdot 6} + \frac{1 \cdot 2}{9 \cdot 2} + \frac{1 \cdot 1}{18 \cdot 1} \\ &= \frac{6 + 2 + 1}{18} \\ &= \frac{9}{18} \\&= \frac{1}{2} \end{aligned} \]