ƒ( x )= 2 x 2 + 3, then ƒ( x - 1)= 2 x 2 + 4 x + 5
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
ƒ( x )= 2 x 2 + 3, then ƒ( x - 1)= 2 x 2 + 4 x + 5
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.