\frac{x+3}{3}-\frac{5x-7}{12}
asked by guest on Apr 02, 2025 at 5:53 pm
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MathBot Answer:
x+33−5x−712=1912−x12\displaystyle \frac{x + 3}{3} - \frac{5 x - 7}{12} = \frac{19}{12} - \frac{x}{12} 3x+3−125x−7=1219−12x
x+33−5x−712=1912−x12\frac{x + 3}{3} - \frac{5 x - 7}{12} = \frac{19}{12} - \frac{x}{12}3x+3−125x−7=1219−12x