9!/(4+2)!

asked by guest
on Jan 12, 2025 at 6:38 pm



You asked:

Evaluate the expression: \(\frac{9!}{\left( 4 + 2 \right)!}\)

MathBot Answer:

\[\frac{9!}{\left( 4 + 2 \right)!} = 504\]


\[\begin{aligned}\frac{9!}{\left( 4 + 2 \right)!}& = 9! \cdot \frac{1}{\left(4 + 2\right)!}\\& = 362880 \cdot \frac{1}{\left(4 + 2\right)!}\\& = 362880 \cdot \frac{1}{6!}\\& = \frac{362880}{720}\\& = 504\end{aligned}\]