9!/(4+2)!
You asked:
Evaluate the expression: \(\frac{9!}{\left( 4 + 2 \right)!}\)
MathBot Answer:
\[\frac{9!}{\left( 4 + 2 \right)!} = 504\]
\[\begin{aligned}\frac{9!}{\left( 4 + 2 \right)!}& = 9! \cdot \frac{1}{\left(4 + 2\right)!}\\& = 362880 \cdot \frac{1}{\left(4 + 2\right)!}\\& = 362880 \cdot \frac{1}{6!}\\& = \frac{362880}{720}\\& = 504\end{aligned}\]