solve y = 120 + 15x, y = 80 + 25x using elimination method
You asked:
Solve the system of equations \(y = 120 + 15 x\), \(y = 80 + 25 x\) by elimination.
MathBot Answer:
\[\begin{aligned}x &= 4\\y &= 180\end{aligned}\]
\[\begin{aligned}- 15 x + y &= 120\\- 25 x + y &= 80\end{aligned}\]
Eliminate \(x\) from equation 2 by multiply both sides of equation 1 by \(- \frac{5}{3}\), and adding the results to both sides of equation 2.
\[\begin{aligned}- 15 x + y &= 120\\- \frac{2 y}{3} &= -120\end{aligned}\]
Solve equation 2 for \(y\), and substitute the solution into the remaining equations.
\[\begin{aligned}- 15 x &= -60\\y &= 180\end{aligned}\]
Solve equation 1 for the remaining unknown \(x\).
\[\begin{aligned}x &= 4\\y &= 180\end{aligned}\]