(n(1) + n(0)) *20.65625

asked by guest
on Jan 28, 2025 at 3:14 pm



You asked:

Evaluate the expression: (n(1)+n(0))20.65625\left(n\left( 1 \right) + n\left( 0 \right)\right) \cdot 20.65625

MathBot Answer:

Evaluated



(n(1)+n(0))20.65625=661n32\displaystyle \left(n\left( 1 \right) + n\left( 0 \right)\right) \cdot 20.65625 = \frac{661 n}{32}


Expanded

(n(1)+n(0))20.65625=661n32\left(n\left( 1 \right) + n\left( 0 \right)\right) \cdot 20.65625 = \frac{661 n}{32}