2,4!

asked by guest
on Mar 17, 2025 at 2:12 am



MathBot Answer:

The sum of 22 and 4!4! is:

=(2)+(4!)=26\begin{aligned}&=\left(2\right) + \left(4!\right) \\\\ &= 26 \\\\\end{aligned}


The difference of 22 and 4!4! is:

=(2)(4!)=22\begin{aligned}&=\left(2\right) - \left(4!\right) \\\\ &= -22 \\\\\end{aligned}


The product of 22 and 4!4! is:

=(2)(4!)=24!=48\begin{aligned}&=\left(2\right) \cdot \left(4!\right) \\\\ &= 2 4! \\\\ &=48 \\\\\end{aligned}


The quotient of 22 and 4!4! is:

=(2)(4!)=112\begin{aligned}&= \frac{\left(2\right)}{\left(4!\right)} \\\\ &= \frac{1}{12} \\\\\end{aligned}