2,4!
asked by guest on Mar 17, 2025 at 2:12 am
MathBot Answer:
The sum of 222 and 4!4!4! is:
=(2)+(4!)=26\begin{aligned}&=\left(2\right) + \left(4!\right) \\\\ &= 26 \\\\\end{aligned}=(2)+(4!)=26
The difference of 222 and 4!4!4! is:
=(2)−(4!)=−22\begin{aligned}&=\left(2\right) - \left(4!\right) \\\\ &= -22 \\\\\end{aligned}=(2)−(4!)=−22
The product of 222 and 4!4!4! is:
=(2)⋅(4!)=24!=48\begin{aligned}&=\left(2\right) \cdot \left(4!\right) \\\\ &= 2 4! \\\\ &=48 \\\\\end{aligned}=(2)⋅(4!)=24!=48
The quotient of 222 and 4!4!4! is:
=(2)(4!)=112\begin{aligned}&= \frac{\left(2\right)}{\left(4!\right)} \\\\ &= \frac{1}{12} \\\\\end{aligned}=(4!)(2)=121
