m^3+27 over m^2-9
You asked:
Evaluate the expression: \({m}^{3} + \frac{27}{{m}^{2}} - 9\)
MathBot Answer:
Evaluated
\(\displaystyle {m}^{3} + \frac{27}{{m}^{2}} - 9 = m^{3} - 9 + \frac{27}{m^{2}} \)
Factored
\[{m}^{3} + \frac{27}{{m}^{2}} - 9 = \frac{m^{5} - 9 m^{2} + 27}{m^{2}}\]