3/4+1/2+1/3

asked by guest
on Jan 29, 2025 at 11:57 am



You asked:

Evaluate the expression: 34+12+13\frac{3}{4} + \frac{1}{2} + \frac{1}{3}

MathBot Answer:

34+12+13=1912=1.583 \frac{3}{4} + \frac{1}{2} + \frac{1}{3} = \frac{19}{12} = 1.58\overline{3}


The sum can be computed by rewriting each term over a common denominator, where the least common denominator of 34\frac{3}{4}, 12\frac{1}{2}, and 13\frac{1}{3} is 1212. 34+12+13=3343+1626+1434=9+6+412=1912 \begin{aligned} \frac{3}{4} + \frac{1}{2} + \frac{1}{3} &= \frac{3 \cdot 3}{4 \cdot 3} + \frac{1 \cdot 6}{2 \cdot 6} + \frac{1 \cdot 4}{3 \cdot 4} \\ &= \frac{9 + 6 + 4}{12} \\ &= \frac{19}{12} \end{aligned}