Math Problem Solver

\[ \frac{1}{4} + \frac{1}{5} + \frac{1}{7} = \frac{83}{140} = 0.59\overline{285714} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{4}\), \(\frac{1}{5}\), and \(\frac{1}{7}\) is \(140\). \[ \begin{aligned} \frac{1}{4} + \frac{1}{5} + \frac{1}{7} &= \frac{1 \cdot 35}{4 \cdot 35} + \frac{1 \cdot 28}{5 \cdot 28} + \frac{1 \cdot 20}{7 \cdot 20} \\ &= \frac{35 + 28 + 20}{140} \\ &= \frac{83}{140} \end{aligned} \]