Math Problem Solver

\[ \frac{5}{6} + \frac{1}{7} = \frac{41}{42} = 0.9\overline{761904} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{5}{6}\) and \(\frac{1}{7}\) is \(42\). \[ \begin{aligned} \frac{5}{6} + \frac{1}{7} &= \frac{5 \cdot 7}{6 \cdot 7} + \frac{1 \cdot 6}{7 \cdot 6} \\ &= \frac{35 + 6}{42} \\ &= \frac{41}{42} \end{aligned} \]