(x ^ { 4 } +3x ^ { 3 } -5x ^ { 2 } +x-7) \div (x+3)

asked by guest
on Mar 26, 2025 at 8:30 pm



You asked:

Evaluate the expression: x4+3x3−5x2+x−7x+3\frac{{x}^{4} + 3 {x}^{3} - 5 {x}^{2} + x - 7}{x + 3}

MathBot Answer:

Evaluated



x4+3x3−5x2+x−7x+3=x4+3x3−5x2+x−7x+3\displaystyle \frac{{x}^{4} + 3 {x}^{3} - 5 {x}^{2} + x - 7}{x + 3} = \frac{x^{4} + 3 x^{3} - 5 x^{2} + x - 7}{x + 3}

Expanded

x4+3x3−5x2+x−7x+3=x4x+3+3x3x+3−5x2x+3+xx+3−7x+3\frac{{x}^{4} + 3 {x}^{3} - 5 {x}^{2} + x - 7}{x + 3} = \frac{x^{4}}{x + 3} + \frac{3 x^{3}}{x + 3} - \frac{5 x^{2}}{x + 3} + \frac{x}{x + 3} - \frac{7}{x + 3}

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