d^2-19d+90
asked by guest on Mar 20, 2025 at 5:56 pm
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MathBot Answer:
d2−19d+90=d2−19d+90\displaystyle {d}^{2} - 19 d + 90 = d^{2} - 19 d + 90 d2−19d+90=d2−19d+90
d2−19d+90=(d−10)(d−9){d}^{2} - 19 d + 90 = \left(d - 10\right) \left(d - 9\right)d2−19d+90=(d−10)(d−9)