Divide 6x^3+6x^2−60x+48 by x+4

asked by guest
on Nov 26, 2024 at 9:38 am



You asked:

Evaluate the expression: \(\frac{6 {x}^{3} + 6 {x}^{2} - 60 x + 48}{x + 4}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{6 {x}^{3} + 6 {x}^{2} - 60 x + 48}{x + 4} = \frac{6 x^{3} + 6 x^{2} - 60 x + 48}{x + 4} \)


Expanded

\[\frac{6 {x}^{3} + 6 {x}^{2} - 60 x + 48}{x + 4} = \frac{6 x^{3}}{x + 4} + \frac{6 x^{2}}{x + 4} - \frac{60 x}{x + 4} + \frac{48}{x + 4}\]


Factored

\[\frac{6 {x}^{3} + 6 {x}^{2} - 60 x + 48}{x + 4} = 6 \left(x - 2\right) \left(x - 1\right)\]