(x+1)(x+2)(x+3)(x+4)-48

asked by guest
on Jan 20, 2025 at 3:15 am



You asked:

Evaluate the expression: \(\left(x + 1\right) \left(x + 2\right) \left(x + 3\right) \left(x + 4\right) - 48\)

MathBot Answer:

Evaluated



\(\displaystyle \left(x + 1\right) \left(x + 2\right) \left(x + 3\right) \left(x + 4\right) - 48 = \left(x + 1\right) \left(x + 2\right) \left(x + 3\right) \left(x + 4\right) - 48 \)

Expanded

\[\left(x + 1\right) \left(x + 2\right) \left(x + 3\right) \left(x + 4\right) - 48 = x^{4} + 10 x^{3} + 35 x^{2} + 50 x - 24\]

Factored

\[\left(x + 1\right) \left(x + 2\right) \left(x + 3\right) \left(x + 4\right) - 48 = \left(x^{2} + 5 x - 2\right) \left(x^{2} + 5 x + 12\right)\]

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