f'(x)=ln[(x^2+4) (x^3+8x+3)^2]

asked by guest
on Oct 24, 2024 at 11:35 pm



You asked:

Investigate the equation: \(f'\left( x \right) = \ln\left( \left({x}^{2} + 4\right) \cdot {\left( {x}^{3} + 8 x + 3 \right)}^{2} \right)\).

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