\frac{-30x^2yz}{36}\div \frac{-5y^2}{7x}
asked by guest on Mar 25, 2025 at 4:23 pm
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MathBot Answer:
−(30x2yz)36−(5y2)7x=7x3z6y\frac{\frac{-\left( 30 {x}^{2} y z \right)}{36}}{\frac{-\left( 5 {y}^{2} \right)}{7 x}} = \frac{7 x^{3} z}{6 y}7x−(5y2)36−(30x2yz)=6y7x3z