factorise 2x^2-x^3-11x+6
You asked:
Factor the expression: \(\displaystyle 2 \cdot {x}^{2} - {x}^{3} - 11 x + 6\)
MathBot Answer:
Factorization over the real numbers:
\[- 11 \cdot \left(0.0909090909090909 x^{3} - 0.181818181818182 x^{2} + 1 x - 0.545454545454545\right)\]Factorization over the complex numbers:
\[- \left(x - \left(\frac{2}{3} + \frac{29}{3 \left(- \frac{1}{2} - \frac{\sqrt{3} i}{2}\right) \sqrt[3]{10 + 3 \sqrt{2721}}} - \frac{\left(- \frac{1}{2} - \frac{\sqrt{3} i}{2}\right) \sqrt[3]{10 + 3 \sqrt{2721}}}{3}\right)\right) \left(x - \left(\frac{2}{3} - \frac{\left(- \frac{1}{2} + \frac{\sqrt{3} i}{2}\right) \sqrt[3]{10 + 3 \sqrt{2721}}}{3} + \frac{29}{3 \left(- \frac{1}{2} + \frac{\sqrt{3} i}{2}\right) \sqrt[3]{10 + 3 \sqrt{2721}}}\right)\right) \left(x - \left(- \frac{\sqrt[3]{10 + 3 \sqrt{2721}}}{3} + \frac{2}{3} + \frac{29}{3 \sqrt[3]{10 + 3 \sqrt{2721}}}\right)\right)\]\(i\) is the imaginary unit, defined as \(i^2 = -1\).