Math Problem Solver

\[ 2\frac{2}{4} + \frac{2}{3} = \frac{19}{6} = 3.1\overline{6} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{2}{1}\), \(\frac{2}{4}\), and \(\frac{2}{3}\) is \(12\). \[ \begin{aligned} 2\frac{2}{4} + \frac{2}{3} &= \frac{2 \cdot 12}{1 \cdot 12} + \frac{2 \cdot 3}{4 \cdot 3} + \frac{2 \cdot 4}{3 \cdot 4} \\ &= \frac{24 + 6 + 8}{12} \\ &= \frac{38}{12} \\&= \frac{19}{6} \end{aligned} \]