128*n^2 + 2528*n + 12481

factorize

asked by guest
on Nov 23, 2024 at 3:05 pm



You asked:

Factor the expression: \(\displaystyle 128 {n}^{2} + 2528 n + 12481\)

MathBot Answer:

Factorization over the real numbers:

\[12481 \cdot \left(0.0102555884945117 n^{2} + 0.202547872766605 n + 1\right)\]

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