(( (-8x^{3}+16)−2x+16) ^{-2x}+16)−2x
asked by guest on Apr 01, 2025 at 1:27 pm
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(−(8x3)+16)−(2x)=(16−8x3)−2x\displaystyle {\left( -\left( 8 {x}^{3} \right) + 16 \right)}^{-\left( 2 x \right)} = \left(16 - 8 x^{3}\right)^{- 2 x} (−(8x3)+16)−(2x)=(16−8x3)−2x
(−(8x3)+16)−(2x)=(16−8x3)−2x{\left( -\left( 8 {x}^{3} \right) + 16 \right)}^{-\left( 2 x \right)} = \left(16 - 8 x^{3}\right)^{- 2 x}(−(8x3)+16)−(2x)=(16−8x3)−2x