10y(6y+21)รท5(2y+7)
You asked:
Evaluate the expression: \(\frac{10 \cdot y \cdot \left(6 y + 21\right)}{5 \cdot \left(2 y + 7\right)}\)
MathBot Answer:
Evaluated
\(\displaystyle \frac{10 \cdot y \cdot \left(6 y + 21\right)}{5 \cdot \left(2 y + 7\right)} = \frac{10 y \left(6 y + 21\right)}{10 y + 35} \)
Expanded
\[\frac{10 \cdot y \cdot \left(6 y + 21\right)}{5 \cdot \left(2 y + 7\right)} = \frac{60 y^{2}}{10 y + 35} + \frac{210 y}{10 y + 35}\]
Factored
\[\frac{10 \cdot y \cdot \left(6 y + 21\right)}{5 \cdot \left(2 y + 7\right)} = 6 y\]