-3^(4)\times \sqrt(32+5(-4)^(3)-5^(2))

asked by guest
on Jan 31, 2025 at 3:44 pm



You asked:

Evaluate the expression: −3432+5(−4)3−52-{3}^{4} \sqrt{32 + 5 {\left( -4 \right)}^{3} - {5}^{2}}

MathBot Answer:

−3432+5(−4)3−52=−81313i-{3}^{4} \sqrt{32 + 5 {\left( -4 \right)}^{3} - {5}^{2}} = - 81 \sqrt{313} i

−3432+5(−4)3−52=−⋅34⋅32+5⋅(−4)3−52=−⋅81⋅32+5⋅(−4)3−52=−⋅81⋅32+5⋅−64−52=−⋅81⋅32−320−52=−⋅81⋅32−320−25=−⋅81⋅−288−25=−⋅81⋅−313=−⋅81⋅i⋅313=−81⋅i⋅313\begin{aligned}-{3}^{4} \sqrt{32 + 5 {\left( -4 \right)}^{3} - {5}^{2}}& = - \cdot 3^{4} \cdot \sqrt{32 + 5 \cdot \left(-4\right)^{3} - 5^{2}}\\& = - \cdot 81 \cdot \sqrt{32 + 5 \cdot \left(-4\right)^{3} - 5^{2}}\\& = - \cdot 81 \cdot \sqrt{32 + 5 \cdot -64 - 5^{2}}\\& = - \cdot 81 \cdot \sqrt{32 - 320 - 5^{2}}\\& = - \cdot 81 \cdot \sqrt{32 - 320 - 25}\\& = - \cdot 81 \cdot \sqrt{-288 - 25}\\& = - \cdot 81 \cdot \sqrt{-313}\\& = - \cdot 81 \cdot i \cdot \sqrt{313}\\& = -81 \cdot i \cdot \sqrt{313}\end{aligned}

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