[ ($2^{2n}$ -3) ($2^{2n-2}$ )( $3^{n}$ -2)( $3^{n-2}$ )] / $3^{n-4}$ ( $4^{n+3}$ - $2^{2n}$ )

asked by guest
on Nov 19, 2024 at 7:14 am



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