½ sin² 210 + ⅔ cos² 240

asked by guest
on Jan 10, 2025 at 6:51 am



You asked:

Evaluate the expression: 12sin⁡(210)2+23cos⁡(240)2\frac{1}{2} {\sin\left( 210 \right)}^{2} + \frac{2}{3} {\cos\left( 240 \right)}^{2}

MathBot Answer:

12sin⁡(210)2+23cos⁡(240)2=2cos⁡2(240)3+sin⁡2(210)2≈0.18013594555782988436304948309517\frac{1}{2} {\sin\left( 210 \right)}^{2} + \frac{2}{3} {\cos\left( 240 \right)}^{2} = \frac{2 \cos^{2}{\left(240 \right)}}{3} + \frac{\sin^{2}{\left(210 \right)}}{2} \approx 0.18013594555782988436304948309517

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