(sin^2 A + sin^2 B - sin^2 C)/(sin A * sin B * sin C) = 2cot C
You asked:
Investigate the equation: \(\frac{{\sin\left( A \right)}^{2} + {\sin\left( B \right)}^{2} - {\sin\left( C \right)}^{2}}{\sin\left( A \right) \cdot \sin\left( B \right) \cdot \sin\left( C \right)} = 2 \cdot \cot\left( C \right)\).