$1 + \frac{\tan(20^\circ)}{\cot(65,5^\circ)}$
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
$1 + \frac{\tan(20^\circ)}{\cot(65,5^\circ)}$
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.