8^{2x}*(1/4)^{x-2}=4^{-x}(1/2)^{2-x}

asked by guest
on Nov 13, 2024 at 11:34 pm



You asked:

Solve the equation \({8}^{2 x} \cdot {\left( \frac{1}{4} \right)}^{x - 2} = {4}^{-x} \cdot {\left( \frac{1}{2} \right)}^{2 - x}\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = - \frac{6}{5} = -1.2\]

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