3.28⋅$t^{0.45}$+0.81
You asked:
Evaluate the expression: \(3.28 \cdot {t}^{0.45} + 0.81\)
MathBot Answer:
Evaluated
\(\displaystyle 3.28 \cdot {t}^{0.45} + 0.81 = \frac{82 t^{\frac{9}{20}}}{25} + \frac{81}{100} \)
Expanded
\[3.28 \cdot {t}^{0.45} + 0.81 = \frac{82 t^{\frac{9}{20}}}{25} + \frac{81}{100}\]