3.28⋅$t^{0.45}$+0.81

asked by guest
on Oct 24, 2024 at 1:23 pm



You asked:

Evaluate the expression: \(3.28 \cdot {t}^{0.45} + 0.81\)

MathBot Answer:

Evaluated



\(\displaystyle 3.28 \cdot {t}^{0.45} + 0.81 = \frac{82 t^{\frac{9}{20}}}{25} + \frac{81}{100} \)

Expanded

\[3.28 \cdot {t}^{0.45} + 0.81 = \frac{82 t^{\frac{9}{20}}}{25} + \frac{81}{100}\]

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