(2*10^-180)+(4*10^-182)
You asked:
MathBot Answer:
\[2 \cdot {10}^{-180} + 4 \cdot {10}^{-182} = \frac{51}{25000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000} \approx -0\]
\[\begin{aligned}2 \cdot {10}^{-180} + 4 \cdot {10}^{-182}& = 2 \cdot \frac{1}{10^{180}} + 4 \cdot \frac{1}{10^{182}}\\& = \frac{2}{1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000} + 4 \cdot \frac{1}{10^{182}}\\& = \frac{1}{500000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000} + 4 \cdot \frac{1}{10^{182}}\\& = \frac{1}{500000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000} + \frac{4}{100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000}\\& = \frac{1}{500000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000} + \frac{1}{25000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000}\\& = \frac{51}{25000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000}\end{aligned}\]