50-30e^-0.2t=50
You asked:
Investigate the equation: \(50 - 30 \cdot {e}^{-0.2} \cdot t = 50\).
MathBot Answer:
The solution is: \[t = 0\]
\[\begin{aligned}t \left(- \frac{30}{e^{0.2}}\right) + 50 &= 50\\t \left(- \frac{30}{e^{0.2}}\right) &= 0\\t &= 0\end{aligned}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).