56/21+9/3(5-40/3)(4+140/7)

asked by guest
on Nov 18, 2024 at 9:22 am



You asked:

Evaluate the expression: \(\frac{56}{21} + \frac{9}{3 \cdot \left(5 - \frac{40}{3}\right) \cdot \left(4 + \frac{140}{7}\right)}\)

MathBot Answer:

\[\frac{56}{21} + \frac{9}{3 \cdot \left(5 - \frac{40}{3}\right) \cdot \left(4 + \frac{140}{7}\right)} = \frac{1591}{600} = 2.651\overline{6}\]

\[\begin{aligned}\frac{56}{21} + \frac{9}{3 \cdot \left(5 - \frac{40}{3}\right) \cdot \left(4 + \frac{140}{7}\right)}& = \frac{56}{21} + 9 \cdot \frac{1}{3 \cdot \left(5 - \frac{40}{3}\right) \cdot \left(4 + \frac{140}{7}\right)}\\& = \frac{56}{21} + 9 \cdot \frac{1}{3 \cdot - \frac{25}{3} \cdot \left(4 + \frac{140}{7}\right)}\\& = \frac{56}{21} + 9 \cdot \frac{1}{3 \cdot - \frac{25}{3} \cdot 24}\\& = \frac{56}{21} + 9 \cdot \frac{1}{-25 \cdot 24}\\& = \frac{56}{21} + \frac{9}{-600}\\& = \frac{56}{21} - \frac{3}{200}\\& = \frac{1591}{600}\end{aligned}\]

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