\frac{1}{1+\log _a\left(bc\right)}+\frac{1}{1+\log _b\left(ac\right)}+\frac{1}{1+\log _c\left(ab\right)}
asked by guest
on Nov 14, 2024 at 6:54 pm
You asked:
Evaluate the expression:
1+loga(bc)1+1+logb(ac)1+1+logc(ab)1
MathBot Answer:
Evaluated
1+loga(bc)1+1+logb(ac)1+1+logc(ab)1=1+log(c)log(ab)1+1+log(b)log(ac)1+1+log(a)log(bc)1
Expanded
1+loga(bc)1+1+logb(ac)1+1+logc(ab)1=1+log(c)log(ab)1+1+log(b)log(ac)1+1+log(a)log(bc)1
Factored
1+loga(bc)1+1+logb(ac)1+1+logc(ab)1=(1+log(a)log(bc))(1+log(b)log(ac))(1+log(c)log(ab))3+log(c)2log(ab)+log(b)2log(ac)+log(b)log(c)log(ab)log(ac)+log(a)2log(bc)+log(a)log(c)log(ab)log(bc)+log(a)log(b)log(ac)log(bc)