$$\int(x^2/sqrt(1-4x^2)) dx$$
You asked:
Evaluate the integral: \(\int{\frac{{x}^{2}}{\sqrt{1 - 4 {x}^{2}}}}dx\)
MathBot Answer:
Antiderivative
\[\int{\frac{{x}^{2}}{\sqrt{1 - 4 {x}^{2}}}}dx = \frac{\arcsin{\left(2 x \right)}}{16} - \frac{\sqrt{1 - 4 x^{2}} x}{8} + C\]