8sin^4( $\pi$ x- $\pi$ /6)-8sin^2( $\pi$ x- $\pi$ /6)=-24/16

asked by guest
on Jan 26, 2025 at 1:56 am



You asked:

Solve the equation \(8 {\sin\left( \pi x - \frac{\pi}{6} \right)}^{4} - 8 {\sin\left( \pi x - \frac{\pi}{6} \right)}^{2} = \frac{-24}{16}\) for the variable \(x\).

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