$$\int(2x^2/x^2+4x/x^2-3/x^2) dx$$
You asked:
Evaluate the integral: \(\int{\frac{2 {x}^{2}}{{x}^{2}} + \frac{4 x}{{x}^{2}} - \frac{3}{{x}^{2}}}dx\)
MathBot Answer:
Antiderivative
\[\int{\frac{2 {x}^{2}}{{x}^{2}} + \frac{4 x}{{x}^{2}} - \frac{3}{{x}^{2}}}dx = 2 x + \frac{3}{x} + 4 \log{\left(x \right)} + C\]