y=2 3y^2 + 10y + 5

asked by guest
on Jan 14, 2025 at 9:53 pm



You asked:

Given \(y = 2\) evaluate \(3 {y}^{2} + 10 y + 5\).

MathBot Answer:

\[3 {y}^{2} + 10 y + 5 = 3 \cdot {2}^{2} + 10 \cdot 2 + 5 = 37\]

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