6a^3+15a^2+6a=120
You asked:
Solve the equation \(6 \cdot {a}^{3} + 15 \cdot {a}^{2} + 6 a = 120\) for the variable \(a\).
MathBot Answer:
The 3 solutions to the equation are: \[\begin{aligned}a &= 2\\a &= - \frac{9}{4} - \frac{\sqrt{79} i}{4} \approx -2.25 -2.2220486 i\\a &= - \frac{9}{4} + \frac{\sqrt{79} i}{4} \approx -2.25 + 2.2220486 i\end{aligned}\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).