(D2D^{2}-4D+3)y=x3x^{3}

asked by guest
on Nov 14, 2024 at 3:20 pm



You asked:

Investigate the equation: (D2−4D+3)⋅y=x3\left({D}^{2} - 4 D + 3\right) \cdot y = {x}^{3}.

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