(1.5*10^-1)-(1*10^-1*10)-(5*10^-2)

asked by guest
on Apr 04, 2025 at 4:37 am



You asked:

Evaluate the expression: 1.5⋅10−1−1⋅10−1⋅10−5⋅10−21.5 \cdot {10}^{-1} - 1 \cdot {10}^{-1} \cdot 10 - 5 \cdot {10}^{-2}

MathBot Answer:

1.5⋅10−1−1⋅10−1⋅10−5⋅10−2=−910=−0.91.5 \cdot {10}^{-1} - 1 \cdot {10}^{-1} \cdot 10 - 5 \cdot {10}^{-2} = - \frac{9}{10} = -0.9

1.5⋅10−1−1⋅10−1⋅10−5⋅10−2=32⋅10−1−1⋅10−1⋅10−5⋅10−2=32⋅110−1⋅10−1⋅10−5⋅10−2=320−1⋅10−1⋅10−5⋅10−2=320−1⋅110⋅10−5⋅10−2=320−110⋅10−5⋅10−2=320−1−5⋅10−2=−1720−5⋅10−2=−1720−5⋅1100=−1720−120=−910\begin{aligned}1.5 \cdot {10}^{-1} - 1 \cdot {10}^{-1} \cdot 10 - 5 \cdot {10}^{-2}&=\frac{3}{2} \cdot {10}^{-1} - 1 \cdot {10}^{-1} \cdot 10 - 5 \cdot {10}^{-2}\\&=\frac{3}{2} \cdot \frac{1}{10} - 1 \cdot {10}^{-1} \cdot 10 - 5 \cdot {10}^{-2}\\&=\frac{3}{20} - 1 \cdot {10}^{-1} \cdot 10 - 5 \cdot {10}^{-2}\\&=\frac{3}{20} - 1 \cdot \frac{1}{10} \cdot 10 - 5 \cdot {10}^{-2}\\&=\frac{3}{20} - \frac{1}{10} \cdot 10 - 5 \cdot {10}^{-2}\\&=\frac{3}{20} - 1 - 5 \cdot {10}^{-2}\\&=\frac{-17}{20} - 5 \cdot {10}^{-2}\\&=\frac{-17}{20} - 5 \cdot \frac{1}{100}\\&=\frac{-17}{20} - \frac{1}{20}\\&=\frac{-9}{10}\end{aligned}

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