Considere a seguinte expressão algébrica:
3
x
3
−
5
x
−
6
x
2
+
10
3x
3
−5x−6x
2
+10
A alternativa que representa a fatoração por agrupamento da expressão é:
(
3
x
−
5
)
(
x
−
2
)
(3x−5)(x−2)
(
3
x
2
+
5
)
(
x
2
+
2
)
(3x
2
+5)(x
2
+2)
(
3
x
2
−
5
)
(
x
−
2
)
(3x
2
−5)(x−2)
(
3
x
+
5
)
(
x
2
)
(3x+5)(x
2
)
(
3
x
−
5
)
(
x
+
2
)
(3x−5)(x+2)
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