$3^{x}$ = $7^{x+2}$

asked by guest
on Jan 15, 2025 at 5:08 am



You asked:

Solve the equation \({3}^{x} = {7}^{x + 2}\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = \frac{2 \log{\left(7 \right)}}{- \log{\left(7 \right)} + \log{\left(3 \right)}} \approx -4.5932139\]