$3^{x}$ = $7^{x+2}$
You asked:
Solve the equation \({3}^{x} = {7}^{x + 2}\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{2 \log{\left(7 \right)}}{- \log{\left(7 \right)} + \log{\left(3 \right)}} \approx -4.5932139\]
$3^{x}$ = $7^{x+2}$
You asked:
MathBot Answer:
The solution is: \[x = \frac{2 \log{\left(7 \right)}}{- \log{\left(7 \right)} + \log{\left(3 \right)}} \approx -4.5932139\]