4xy+1.8y=27

asked by guest
on Oct 25, 2024 at 3:33 am



You asked:

Investigate the equation: \(4 x y + 1.8 y = 27\).

MathBot Answer:

The graph of the equation \(4 x y + 1.8 y = 27\) is a hyperbola.

The coordinates of its foci are: \(\left(- \frac{3 \sqrt{6}}{2} - \frac{9}{20}, - \frac{3 \sqrt{6}}{2}\right)\) and \(\left(- \frac{9}{20} + \frac{3 \sqrt{6}}{2}, \frac{3 \sqrt{6}}{2}\right)\).

The coordinates of its vertices are: \(\left(- \frac{3 \sqrt{3}}{2} - \frac{9}{20}, - \frac{3 \sqrt{3}}{2}\right)\) and \(\left(- \frac{9}{20} + \frac{3 \sqrt{3}}{2}, \frac{3 \sqrt{3}}{2}\right)\).

The asymptotes have equations: \(- 60 \sqrt{3} x - 27 \sqrt{3} = 0\) and \(- 60 \sqrt{3} y = 0\).

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