a+b*c=189

d+a+a=25

d+d+b=24

d+c*b=?

asked by guest
on Nov 14, 2024 at 8:21 pm



MathBot Answer:

The system of equations has infinitely many solutions.

a=252−d2b=24−2dc=−d+3534(d−12)\begin{aligned}a &= \frac{25}{2} - \frac{d}{2}\\b &= 24 - 2 d\\c &= - \frac{d + 353}{4 \left(d - 12\right)}\end{aligned}

dd is a free variable.

By substituting these values into the expression, we find that: bc+d=3d2+3532\begin{aligned}b c + d &= \frac{3 d}{2} + \frac{353}{2}\end{aligned}

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