a+b*c=189
d+a+a=25
d+d+b=24
d+c*b=?
You asked:
Given the following equations: \[\begin{aligned}a + b c &= 189\\ d + a + a &= 25\\ d + d + b &= 24\end{aligned}\] Evaluate \(d + c b\).
MathBot Answer:
The system of equations has infinitely many solutions.
$$\begin{aligned}a &= \frac{25}{2} - \frac{d}{2}\\b &= 24 - 2 d\\c &= - \frac{d + 353}{4 \left(d - 12\right)}\end{aligned}$$
\(d\) is a free variable.
By substituting these values into the expression, we find that: $$\begin{aligned}b c + d &= \frac{3 d}{2} + \frac{353}{2}\end{aligned}$$