(2*10^-180)+(2*10^-182)

asked by guest
on Nov 25, 2024 at 11:36 am



You asked:

Evaluate the expression: \(2 \cdot {10}^{-180} + 2 \cdot {10}^{-182}\)

MathBot Answer:

\[2 \cdot {10}^{-180} + 2 \cdot {10}^{-182} = \frac{101}{50000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000} \approx -0\]

\[\begin{aligned}2 \cdot {10}^{-180} + 2 \cdot {10}^{-182}& = 2 \cdot \frac{1}{10^{180}} + 2 \cdot \frac{1}{10^{182}}\\& = \frac{2}{1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000} + 2 \cdot \frac{1}{10^{182}}\\& = \frac{1}{500000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000} + 2 \cdot \frac{1}{10^{182}}\\& = \frac{1}{500000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000} + \frac{2}{100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000}\\& = \frac{1}{500000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000} + \frac{1}{50000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000}\\& = \frac{101}{50000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000}\end{aligned}\]

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