2422.229=74+2360*2.718^(0.06*a)
You asked:
Solve the equation \(2422.229 = 74 + 2360 \cdot {2.718}^{0.06 a}\) for the variable \(a\).
MathBot Answer:
The solution is: \[a = \frac{50 \left(- \log{\left(2360000 \right)} + \log{\left(2348229 \right)}\right)}{3 \left(- 3 \log{\left(5 \right)} - 2 \log{\left(2 \right)} + 2 \log{\left(3 \right)} + \log{\left(151 \right)}\right)} \approx -0.083345175\]