x^{2}* lne^{x^{2}}d
You asked:
Evaluate the expression: \({x}^{2} \ln\left( {e}^{{x}^{2}} d \right)\)
MathBot Answer:
\[{x}^{2} \ln\left( {e}^{{x}^{2}} d \right) = x^{2} \log{\left(d e^{x^{2}} \right)}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).