5($17.2^{x+4}$ )( $8.6^{2x}$ ) = $4.7^{x-1}$

asked by guest
on Nov 16, 2024 at 10:56 am



You asked:

Solve the equation \(5 \cdot {17.2}^{x + 4} \cdot {8.6}^{2 x} = {4.7}^{x - 1}\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = - \frac{- 4 \log{\left(5 \right)} + \log{\left(1285469176 \right)}}{- \log{\left(5 \right)} - \log{\left(235 \right)} + \log{\left(2 \right)} + \log{\left(159014 \right)}} \approx -2.5954244\]