Let

{

š‘Ž

š‘›

}

š‘›

=

1

āˆž

{a

n

ā€‹

}

n=1

āˆž

ā€‹

be a sequence of positive numbers such that:

š‘Ž

1

ā‰„

š‘Ž

2

ā‰„

š‘Ž

3

ā‰„

ā‹Æ

ā‰„

š‘Ž

š‘›

ā‰„

š‘Ž

š‘›

+

1

ā‰„

ā‹Æ

a

1

ā€‹

ā‰„a

2

ā€‹

ā‰„a

3

ā€‹

ā‰„ā‹Æā‰„a

n

ā€‹

ā‰„a

n+1

ā€‹

ā‰„ā‹Æ (i.e., the sequence is non-increasing).

lim

ā”

š‘›

ā†’

āˆž

š‘Ž

š‘›

=

0.

lim

nā†’āˆž

ā€‹

a

n

ā€‹

=0.

Then the alternating series

āˆ‘

š‘›

=

1

āˆž

(

āˆ’

1

)

š‘›

+

1

š‘Ž

š‘›

āˆ‘

n=1

āˆž

ā€‹

(āˆ’1)

n+1

a

n

ā€‹

is convergent.

asked by guest
on Oct 24, 2024 at 11:22 am



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.